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13	13	* **時刻ｔでの高さｙが障害物の高さｈよりも上であればよいので、**
14	14	** [[image:http://www.dietpanda.com/cgi-bin/mimetex.cgi?h<u(t-t_0)-\frac{1}{2}g(t-t_0)^2]] 　**これに、上記のｕ、ｔ、ｔ,,0,,を代入すると、**
15		-\\[[image:http://www.dietpanda.com/cgi-bin/mimetex.cgi?h<2\sqrt{gh}(\frac{L}{v}-4\sqrt{hg})-\frac{1}{2}g(\frac{L}{v}-4\sqrt{hg})^2||height="30" width="339"]]
	15	+\\[[image:http://www.dietpanda.com/cgi-bin/mimetex.cgi?h<2\sqrt{gh}(\frac{L}{v}-4\sqrt{hg})-\frac{1}{2}g(\frac{L}{v}-4\sqrt{hg})^2||height="30" width="339"]]　[[image:http://www.dietpanda.com/cgi-bin/mimetex.cgi?h<2\sqrt{gh}||alt="http://www.dietpanda.com/cgi-bin/mimetex.cgi?h<2\sqrt{gh}(\frac{L}{v}-4\sqrt{hg})-\frac{1}{2}g(\frac{L}{v}-4\sqrt{hg})^2" height="20" width="76"]][[image:http://www.dietpanda.com/cgi-bin/mimetex.cgi?(\frac{L}{v}-4\sqrt{hg})-\frac{1}{2}g||alt="http://www.dietpanda.com/cgi-bin/mimetex.cgi?h<2\sqrt{gh}(\frac{L}{v}-4\sqrt{hg})-\frac{1}{2}g(\frac{L}{v}-4\sqrt{hg})^2" height="30" width="141"]][[image:http://www.dietpanda.com/cgi-bin/mimetex.cgi?(\frac{L}{v}-4\sqrt{hg})^2||alt="http://www.dietpanda.com/cgi-bin/mimetex.cgi?h<2\sqrt{gh}(\frac{L}{v}-4\sqrt{hg})-\frac{1}{2}g(\frac{L}{v}-4\sqrt{hg})^2" height="30" width="137"]]
16	16	\\[[image:http://www.dietpanda.com/cgi-bin/mimetex.cgi?h<2\frac{L}{v}\sqrt{gh}-8h-\frac{1}{2}g\frac{L^2}{v^2}-8h+4\frac{L}{v}\sqrt{gh}||height="40" width="345"]]
17	17	\\[[image:http://www.dietpanda.com/cgi-bin/mimetex.cgi?0<6\sqrt{gh}\frac{L}{v}-17h-\frac{1}{2}g\frac{L^2}{v^2}||height="43" width="250"]]　**これを、ｖの二次不等式に直すと、**
18	18	\\[[image:http://www.dietpanda.com/cgi-bin/mimetex.cgi?0>34v^2-12\sqrt{\frac{g}{h}}Lv+\frac{g}{h}L^2||alt="http://www.dietpanda.com/cgi-bin/mimetex.cgi?0>34v^2-12\sqrt{gh}v+\frac{g}{h}" height="40" width="200"]] 　**さらに、＝０の二次方程式としてvを求めると、**